13230101133331 has 2 divisors, whose sum is σ = 13230101133332. Its totient is φ = 13230101133330.

The previous prime is 13230101133313. The next prime is 13230101133367. The reversal of 13230101133331 is 13333110103231.

Together with previous prime (13230101133313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13230101133331 - 2²¹ = 13230099036179 is a prime.

It is a super-3 number, since 3×13230101133331³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13230101133296 and 13230101133305.

It is not a weakly prime, because it can be changed into another prime (13230101133371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615050566665 + 6615050566666.

It is an arithmetic number, because the mean of its divisors is an integer number (6615050566666).

Almost surely, 2^{13230101133331} is an apocalyptic number.

13230101133331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13230101133331 is an equidigital number, since it uses as much as digits as its factorization.

13230101133331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 13230101133331 its reverse (13333110103231), we get a palindrome (26563211236562).

The spelling of 13230101133331 in words is "thirteen trillion, two hundred thirty billion, one hundred one million, one hundred thirty-three thousand, three hundred thirty-one".