Base | Representation |
---|---|
bin | 11110000101001111000110… |
… | …010010110010010011100111 |
3 | 122100102212112102010122201102 |
4 | 132011033012102302103213 |
5 | 114320110331313311403 |
6 | 1145214200111150315 |
7 | 36603306115510100 |
oct | 3605170622622347 |
9 | 570385472118642 |
10 | 132301204432103 |
11 | 391786978a8a43 |
12 | 12a08a3981539b |
13 | 58a8c47331a75 |
14 | 24955abb153a7 |
15 | 10466d0848b88 |
hex | 7853c64b24e7 |
132301204432103 has 24 divisors (see below), whose sum is σ = 155592446234400. Its totient is φ = 112156569520128.
The previous prime is 132301204432097. The next prime is 132301204432129. The reversal of 132301204432103 is 301234402103231.
It is not a de Polignac number, because 132301204432103 - 212 = 132301204428007 is a prime.
It is a super-2 number, since 2×1323012044321032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132301204432153) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2269763 + ... + 16424196.
It is an arithmetic number, because the mean of its divisors is an integer number (6483018593100).
Almost surely, 2132301204432103 is an apocalyptic number.
132301204432103 is a deficient number, since it is larger than the sum of its proper divisors (23291241802297).
132301204432103 is a wasteful number, since it uses less digits than its factorization.
132301204432103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18695559 (or 18695552 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 132301204432103 its reverse (301234402103231), we get a palindrome (433535606535334).
The spelling of 132301204432103 in words is "one hundred thirty-two trillion, three hundred one billion, two hundred four million, four hundred thirty-two thousand, one hundred three".
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