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13230131211043 is a prime number
BaseRepresentation
bin1100000010000110000101…
…0001010110101100100011
31201211210021120222022212021
43000201201101112230203
53213230302042223133
644045501031042311
72533562661540625
oct300414121265443
951753246868767
1013230131211043
11424095a1837aa
121598108210397
1374c7995c0446
1433a4adb48c15
1517e22d00252d
hexc0861456b23

13230131211043 has 2 divisors, whose sum is σ = 13230131211044. Its totient is φ = 13230131211042.

The previous prime is 13230131210999. The next prime is 13230131211049. The reversal of 13230131211043 is 34011213103231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13230131211043 - 213 = 13230131202851 is a prime.

It is a super-2 number, since 2×132301312110432 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13230131210999 and 13230131211017.

It is not a weakly prime, because it can be changed into another prime (13230131211049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615065605521 + 6615065605522.

It is an arithmetic number, because the mean of its divisors is an integer number (6615065605522).

Almost surely, 213230131211043 is an apocalyptic number.

13230131211043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13230131211043 is an equidigital number, since it uses as much as digits as its factorization.

13230131211043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13230131211043 its reverse (34011213103231), we get a palindrome (47241344314274).

The spelling of 13230131211043 in words is "thirteen trillion, two hundred thirty billion, one hundred thirty-one million, two hundred eleven thousand, forty-three".