Base | Representation |
---|---|
bin | 1100000010000110000111… |
… | …0111000101111110010110 |
3 | 1201211210022021120221110220 |
4 | 3000201201313011332112 |
5 | 3213230312110312042 |
6 | 44045502023055210 |
7 | 2533563141613263 |
oct | 300414167057626 |
9 | 51753267527426 |
10 | 13230141104022 |
11 | 4240964820517 |
12 | 159810b5a1506 |
13 | 74c79b67538b |
14 | 33a4b11a226a |
15 | 17e22dd088ec |
hex | c0861dc5f96 |
13230141104022 has 16 divisors (see below), whose sum is σ = 26469907662000. Its totient is φ = 4408442792352.
The previous prime is 13230141104017. The next prime is 13230141104023. The reversal of 13230141104022 is 22040114103231.
It is a junction number, because it is equal to n+sod(n) for n = 13230141103983 and 13230141104001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13230141104023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 401042713 + ... + 401075700.
It is an arithmetic number, because the mean of its divisors is an integer number (1654369228875).
Almost surely, 213230141104022 is an apocalyptic number.
13230141104022 is an abundant number, since it is smaller than the sum of its proper divisors (13239766557978).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13230141104022 is a wasteful number, since it uses less digits than its factorization.
13230141104022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 802121167.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13230141104022 its reverse (22040114103231), we get a palindrome (35270255207253).
The spelling of 13230141104022 in words is "thirteen trillion, two hundred thirty billion, one hundred forty-one million, one hundred four thousand, twenty-two".
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