Base | Representation |
---|---|
bin | 11110000101001111111011… |
… | …101011010000100101110110 |
3 | 122100102221211211101020212021 |
4 | 132011033323223100211312 |
5 | 114320114200102240204 |
6 | 1145214425023143354 |
7 | 36603340242164020 |
oct | 3605177353204566 |
9 | 570387754336767 |
10 | 132302100040054 |
11 | 391790074004aa |
12 | 12a09049744b5a |
13 | 58a905aa4b2b9 |
14 | 2495654a4b010 |
15 | 10467342a9154 |
hex | 7853fbad0976 |
132302100040054 has 8 divisors (see below), whose sum is σ = 226803600068688. Its totient is φ = 56700900017160.
The previous prime is 132302100040043. The next prime is 132302100040063. The reversal of 132302100040054 is 450040001203231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4725075001417 + ... + 4725075001444.
It is an arithmetic number, because the mean of its divisors is an integer number (28350450008586).
Almost surely, 2132302100040054 is an apocalyptic number.
132302100040054 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
132302100040054 is a deficient number, since it is larger than the sum of its proper divisors (94501500028634).
132302100040054 is an equidigital number, since it uses as much as digits as its factorization.
132302100040054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9450150002870.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 132302100040054 its reverse (450040001203231), we get a palindrome (582342101243285).
The spelling of 132302100040054 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred million, forty thousand, fifty-four".
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