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132302100040054 = 279450150002861
BaseRepresentation
bin11110000101001111111011…
…101011010000100101110110
3122100102221211211101020212021
4132011033323223100211312
5114320114200102240204
61145214425023143354
736603340242164020
oct3605177353204566
9570387754336767
10132302100040054
11391790074004aa
1212a09049744b5a
1358a905aa4b2b9
142495654a4b010
1510467342a9154
hex7853fbad0976

132302100040054 has 8 divisors (see below), whose sum is σ = 226803600068688. Its totient is φ = 56700900017160.

The previous prime is 132302100040043. The next prime is 132302100040063. The reversal of 132302100040054 is 450040001203231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4725075001417 + ... + 4725075001444.

It is an arithmetic number, because the mean of its divisors is an integer number (28350450008586).

Almost surely, 2132302100040054 is an apocalyptic number.

132302100040054 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

132302100040054 is a deficient number, since it is larger than the sum of its proper divisors (94501500028634).

132302100040054 is an equidigital number, since it uses as much as digits as its factorization.

132302100040054 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9450150002870.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 132302100040054 its reverse (450040001203231), we get a palindrome (582342101243285).

The spelling of 132302100040054 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred million, forty thousand, fifty-four".

Divisors: 1 2 7 14 9450150002861 18900300005722 66151050020027 132302100040054