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132302140550044 = 2249811664020701
BaseRepresentation
bin11110000101001111111110…
…000101110010101110011100
3122100102221221122121101010021
4132011033332011302232130
5114320114240440100134
61145214433031321524
736603341243414653
oct3605177605625634
9570387848541107
10132302140550044
113917902825a233
1212a0905b2202a4
1358a9066262cca
14249565a19419a
151046737b0c0b4
hex7853fe172b9c

132302140550044 has 12 divisors (see below), whose sum is σ = 231533394456168. Its totient is φ = 66149742134000.

The previous prime is 132302140550039. The next prime is 132302140550059. The reversal of 132302140550044 is 440055041203231.

It is a junction number, because it is equal to n+sod(n) for n = 132302140549991 and 132302140550009.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331811107 + ... + 332209594.

It is an arithmetic number, because the mean of its divisors is an integer number (19294449538014).

Almost surely, 2132302140550044 is an apocalyptic number.

It is an amenable number.

132302140550044 is a deficient number, since it is larger than the sum of its proper divisors (99231253906124).

132302140550044 is a wasteful number, since it uses less digits than its factorization.

132302140550044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 664070516 (or 664070514 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 132302140550044 its reverse (440055041203231), we get a palindrome (572357181753275).

The spelling of 132302140550044 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred forty million, five hundred fifty thousand, forty-four".

Divisors: 1 2 4 49811 99622 199244 664020701 1328041402 2656082804 33075535137511 66151070275022 132302140550044