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1323022200341 is a prime number
BaseRepresentation
bin10011010000001010010…
…001001010111000010101
311200110221200200101221212
4103100022101022320111
5133134022140402331
62451442113151205
7164404503103112
oct23201221127025
94613850611855
101323022200341
114700aa5a5046
121944b155b505
13979b695a3aa
144806adb5909
152463516cd2b
hex1340a44ae15

1323022200341 has 2 divisors, whose sum is σ = 1323022200342. Its totient is φ = 1323022200340.

The previous prime is 1323022200329. The next prime is 1323022200359. The reversal of 1323022200341 is 1430022203231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1315941651025 + 7080549316 = 1147145^2 + 84146^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323022200341 is a prime.

It is a super-2 number, since 2×13230222003412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323022200641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661511100170 + 661511100171.

It is an arithmetic number, because the mean of its divisors is an integer number (661511100171).

Almost surely, 21323022200341 is an apocalyptic number.

It is an amenable number.

1323022200341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323022200341 is an equidigital number, since it uses as much as digits as its factorization.

1323022200341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 1323022200341 its reverse (1430022203231), we get a palindrome (2753044403572).

The spelling of 1323022200341 in words is "one trillion, three hundred twenty-three billion, twenty-two million, two hundred thousand, three hundred forty-one".