Base | Representation |
---|---|
bin | 11110000101010000010000… |
… | …001000110011111110111010 |
3 | 122100102222201202100021012210 |
4 | 132011100100020303332322 |
5 | 114320120400443102024 |
6 | 1145214523045115550 |
7 | 36603351611130531 |
oct | 3605202010637672 |
9 | 570388652307183 |
10 | 132302443331514 |
11 | 39179173163455 |
12 | 12a091246b8bb6 |
13 | 58a90b3bc5b41 |
14 | 249568848d318 |
15 | 10467544ba129 |
hex | 785410233fba |
132302443331514 has 64 divisors (see below), whose sum is σ = 269224240665600. Its totient is φ = 43335455974272.
The previous prime is 132302443331497. The next prime is 132302443331593. The reversal of 132302443331514 is 415133344203231.
It is a happy number.
It is a super-2 number, since 2×1323024433315142 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 736072947 + ... + 736252665.
It is an arithmetic number, because the mean of its divisors is an integer number (4206628760400).
Almost surely, 2132302443331514 is an apocalyptic number.
132302443331514 is an abundant number, since it is smaller than the sum of its proper divisors (136921797334086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132302443331514 is a wasteful number, since it uses less digits than its factorization.
132302443331514 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186019.
The product of its (nonzero) digits is 311040, while the sum is 39.
Adding to 132302443331514 its reverse (415133344203231), we get a palindrome (547435787534745).
The spelling of 132302443331514 in words is "one hundred thirty-two trillion, three hundred two billion, four hundred forty-three million, three hundred thirty-one thousand, five hundred fourteen".
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