Base | Representation |
---|---|
bin | 11110000101010000110011… |
… | …001011010110110111111111 |
3 | 122100110001020201112010221001 |
4 | 132011100303023112313333 |
5 | 114320123101441420104 |
6 | 1145215101245151131 |
7 | 36603402310005541 |
oct | 3605206313266777 |
9 | 570401221463831 |
10 | 132303031201279 |
11 | 39179444a86734 |
12 | 12a0926955b4a7 |
13 | 58a9178935383 |
14 | 2495702599691 |
15 | 104678adddaa4 |
hex | 7854332d6dff |
132303031201279 has 2 divisors, whose sum is σ = 132303031201280. Its totient is φ = 132303031201278.
The previous prime is 132303031201273. The next prime is 132303031201303. The reversal of 132303031201279 is 972102130303231.
It is a weak prime.
It is an emirp because it is prime and its reverse (972102130303231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132303031201279 - 25 = 132303031201247 is a prime.
It is a super-3 number, since 3×1323030312012793 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132303031201273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151515600639 + 66151515600640.
It is an arithmetic number, because the mean of its divisors is an integer number (66151515600640).
Almost surely, 2132303031201279 is an apocalyptic number.
132303031201279 is a deficient number, since it is larger than the sum of its proper divisors (1).
132303031201279 is an equidigital number, since it uses as much as digits as its factorization.
132303031201279 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 37.
The spelling of 132303031201279 in words is "one hundred thirty-two trillion, three hundred three billion, thirty-one million, two hundred one thousand, two hundred seventy-nine".
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