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132303310331 is a prime number
BaseRepresentation
bin111101100110111100…
…1000100110111111011
3110122111110000112101212
41323031321010313323
54131424121412311
6140440155033335
712362412403553
oct1731571046773
9418443015355
10132303310331
1151122851295
122178413b84b
13c62613865a
14659135a163
15369518ac8b
hex1ecde44dfb

132303310331 has 2 divisors, whose sum is σ = 132303310332. Its totient is φ = 132303310330.

The previous prime is 132303310309. The next prime is 132303310333. The reversal of 132303310331 is 133013303231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132303310331 - 230 = 131229568507 is a prime.

It is a super-2 number, since 2×1323033103312 (a number of 23 digits) contains 22 as substring.

Together with 132303310333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132303310297 and 132303310306.

It is not a weakly prime, because it can be changed into another prime (132303310333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151655165 + 66151655166.

It is an arithmetic number, because the mean of its divisors is an integer number (66151655166).

Almost surely, 2132303310331 is an apocalyptic number.

132303310331 is a deficient number, since it is larger than the sum of its proper divisors (1).

132303310331 is an equidigital number, since it uses as much as digits as its factorization.

132303310331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 132303310331 its reverse (133013303231), we get a palindrome (265316613562).

The spelling of 132303310331 in words is "one hundred thirty-two billion, three hundred three million, three hundred ten thousand, three hundred thirty-one".