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132303434556989 is a prime number
BaseRepresentation
bin11110000101010001001011…
…001110000010011000111101
3122100110002021211111201221102
4132011101023032002120331
5114320124413221310424
61145215205254342445
736603415305324653
oct3605211316023075
9570402254451842
10132303434556989
1139179631733863
1212a0936065aa25
1358a92113801a7
14249573dd94dd3
1510467b15167ae
hex78544b38263d

132303434556989 has 2 divisors, whose sum is σ = 132303434556990. Its totient is φ = 132303434556988.

The previous prime is 132303434556973. The next prime is 132303434557013. The reversal of 132303434556989 is 989655434303231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123386730929764 + 8916703627225 = 11107958^2 + 2986085^2 .

It is a cyclic number.

It is not a de Polignac number, because 132303434556989 - 24 = 132303434556973 is a prime.

It is a super-2 number, since 2×1323034345569892 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132303434556959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151717278494 + 66151717278495.

It is an arithmetic number, because the mean of its divisors is an integer number (66151717278495).

Almost surely, 2132303434556989 is an apocalyptic number.

It is an amenable number.

132303434556989 is a deficient number, since it is larger than the sum of its proper divisors (1).

132303434556989 is an equidigital number, since it uses as much as digits as its factorization.

132303434556989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 251942400, while the sum is 65.

The spelling of 132303434556989 in words is "one hundred thirty-two trillion, three hundred three billion, four hundred thirty-four million, five hundred fifty-six thousand, nine hundred eighty-nine".