Base | Representation |
---|---|
bin | 10011010000001011011… |
… | …110010111000000111011 |
3 | 11200111000002202102212112 |
4 | 103100023132113000323 |
5 | 133134042330411011 |
6 | 2451444115002535 |
7 | 164405140100504 |
oct | 23201336270073 |
9 | 4614002672775 |
10 | 1323042435131 |
11 | 47010aa6580a |
12 | 1944b829944b |
13 | 979babc3641 |
14 | 4806d961bab |
15 | 24636d1858b |
hex | 1340b79703b |
1323042435131 has 2 divisors, whose sum is σ = 1323042435132. Its totient is φ = 1323042435130.
The previous prime is 1323042435103. The next prime is 1323042435157. The reversal of 1323042435131 is 1315342403231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1323042435131 - 218 = 1323042172987 is a prime.
It is a super-2 number, since 2×13230424351312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1323042435181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661521217565 + 661521217566.
It is an arithmetic number, because the mean of its divisors is an integer number (661521217566).
Almost surely, 21323042435131 is an apocalyptic number.
1323042435131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323042435131 is an equidigital number, since it uses as much as digits as its factorization.
1323042435131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 1323042435131 its reverse (1315342403231), we get a palindrome (2638384838362).
The spelling of 1323042435131 in words is "one trillion, three hundred twenty-three billion, forty-two million, four hundred thirty-five thousand, one hundred thirty-one".
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