Base | Representation |
---|---|
bin | 1100000010000111001011… |
… | …0111001010000000111111 |
3 | 1201211211001011022002102021 |
4 | 3000201302313022000333 |
5 | 3213231403120130442 |
6 | 44045550212341011 |
7 | 2533603204203334 |
oct | 300416267120077 |
9 | 51754034262367 |
10 | 13230426333247 |
11 | 4240aa0826452 |
12 | 159818b014767 |
13 | 74c8157a0c76 |
14 | 33a4db00c98b |
15 | 17e248d9ae67 |
hex | c0872dca03f |
13230426333247 has 2 divisors, whose sum is σ = 13230426333248. Its totient is φ = 13230426333246.
The previous prime is 13230426333221. The next prime is 13230426333301. The reversal of 13230426333247 is 74233362403231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13230426333247 - 27 = 13230426333119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13230426333217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615213166623 + 6615213166624.
It is an arithmetic number, because the mean of its divisors is an integer number (6615213166624).
Almost surely, 213230426333247 is an apocalyptic number.
13230426333247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230426333247 is an equidigital number, since it uses as much as digits as its factorization.
13230426333247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 43.
Adding to 13230426333247 its reverse (74233362403231), we get a palindrome (87463788736478).
It can be divided in two parts, 1323042 and 6333247, that added together give a square (7656289 = 27672).
The spelling of 13230426333247 in words is "thirteen trillion, two hundred thirty billion, four hundred twenty-six million, three hundred thirty-three thousand, two hundred forty-seven".
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