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132304442043407 is a prime number
BaseRepresentation
bin11110000101010010000111…
…010001010010110000001111
3122100110011220001021100111012
4132011102013101102300033
5114320133444130342112
61145215453244315435
736603452260656104
oct3605220721226017
9570404801240435
10132304442043407
1139179aa9400267
1212a095a1b42b7b
1358a934200baba
1424957d7ad0aab
15104681ebc6022
hex785487452c0f

132304442043407 has 2 divisors, whose sum is σ = 132304442043408. Its totient is φ = 132304442043406.

The previous prime is 132304442043299. The next prime is 132304442043419. The reversal of 132304442043407 is 704340244403231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132304442043407 - 216 = 132304441977871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132304442043607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66152221021703 + 66152221021704.

It is an arithmetic number, because the mean of its divisors is an integer number (66152221021704).

Almost surely, 2132304442043407 is an apocalyptic number.

132304442043407 is a deficient number, since it is larger than the sum of its proper divisors (1).

132304442043407 is an equidigital number, since it uses as much as digits as its factorization.

132304442043407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 774144, while the sum is 41.

Adding to 132304442043407 its reverse (704340244403231), we get a palindrome (836644686446638).

The spelling of 132304442043407 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred forty-two million, forty-three thousand, four hundred seven".