Base | Representation |
---|---|
bin | 11110000101010010000111… |
… | …010001010010110000001111 |
3 | 122100110011220001021100111012 |
4 | 132011102013101102300033 |
5 | 114320133444130342112 |
6 | 1145215453244315435 |
7 | 36603452260656104 |
oct | 3605220721226017 |
9 | 570404801240435 |
10 | 132304442043407 |
11 | 39179aa9400267 |
12 | 12a095a1b42b7b |
13 | 58a934200baba |
14 | 24957d7ad0aab |
15 | 104681ebc6022 |
hex | 785487452c0f |
132304442043407 has 2 divisors, whose sum is σ = 132304442043408. Its totient is φ = 132304442043406.
The previous prime is 132304442043299. The next prime is 132304442043419. The reversal of 132304442043407 is 704340244403231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132304442043407 - 216 = 132304441977871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132304442043607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66152221021703 + 66152221021704.
It is an arithmetic number, because the mean of its divisors is an integer number (66152221021704).
Almost surely, 2132304442043407 is an apocalyptic number.
132304442043407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132304442043407 is an equidigital number, since it uses as much as digits as its factorization.
132304442043407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 774144, while the sum is 41.
Adding to 132304442043407 its reverse (704340244403231), we get a palindrome (836644686446638).
The spelling of 132304442043407 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred forty-two million, forty-three thousand, four hundred seven".
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