Base | Representation |
---|---|
bin | 1100000010000111111010… |
… | …0001100111101110100011 |
3 | 1201211211112210111201110022 |
4 | 3000201332201213232203 |
5 | 3213232303213424441 |
6 | 44050021442424055 |
7 | 2533611101362256 |
oct | 300417641475643 |
9 | 51754483451408 |
10 | 13230622014371 |
11 | 4241091229593 |
12 | 159822466202b |
13 | 74c8471a5508 |
14 | 33a518dc909d |
15 | 17e25b15084b |
hex | c087e867ba3 |
13230622014371 has 2 divisors, whose sum is σ = 13230622014372. Its totient is φ = 13230622014370.
The previous prime is 13230622014343. The next prime is 13230622014373. The reversal of 13230622014371 is 17341022603231.
13230622014371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13230622014371 - 234 = 13213442145187 is a prime.
Together with 13230622014373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13230622014373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615311007185 + 6615311007186.
It is an arithmetic number, because the mean of its divisors is an integer number (6615311007186).
Almost surely, 213230622014371 is an apocalyptic number.
13230622014371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230622014371 is an equidigital number, since it uses as much as digits as its factorization.
13230622014371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
The spelling of 13230622014371 in words is "thirteen trillion, two hundred thirty billion, six hundred twenty-two million, fourteen thousand, three hundred seventy-one".
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