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132310244133304 = 2351846731899389
BaseRepresentation
bin11110000101010111100001…
…000110100000100110111000
3122100110201212101221001112121
4132011113201012200212320
5114320232334444231204
61145222253111251024
736604046122633066
oct3605274106404670
9570421771831477
10132310244133304
1139181506546286
1212a0a741079a74
1358a9a580a28a3
142495bc8503036
151046a5e268b54
hex7855e11a09b8

132310244133304 has 16 divisors (see below), whose sum is σ = 248082194017800. Its totient is φ = 66154992395232.

The previous prime is 132310244133271. The next prime is 132310244133311. The reversal of 132310244133304 is 403331442013231.

It is a super-2 number, since 2×1323102441333042 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132310244133304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11801959 + ... + 20097430.

Almost surely, 2132310244133304 is an apocalyptic number.

It is an amenable number.

132310244133304 is a deficient number, since it is larger than the sum of its proper divisors (115771949884496).

132310244133304 is a wasteful number, since it uses less digits than its factorization.

132310244133304 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32417862 (or 32417858 counting only the distinct ones).

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 132310244133304 its reverse (403331442013231), we get a palindrome (535641686146535).

The spelling of 132310244133304 in words is "one hundred thirty-two trillion, three hundred ten billion, two hundred forty-four million, one hundred thirty-three thousand, three hundred four".

Divisors: 1 2 4 8 518467 1036934 2073868 4147736 31899389 63798778 127597556 255195112 16538780516663 33077561033326 66155122066652 132310244133304