Base | Representation |
---|---|
bin | 1100000010001001011100… |
… | …1001011110001000010111 |
3 | 1201211212121120211100121211 |
4 | 3000202113021132020113 |
5 | 3213234124442122012 |
6 | 44050130440522251 |
7 | 2533624245563344 |
oct | 300422711361027 |
9 | 51755546740554 |
10 | 13231035114007 |
11 | 4241283431447 |
12 | 159831aa80387 |
13 | 74c8b1952479 |
14 | 33a557bdd7cb |
15 | 17e2825506a7 |
hex | c089725e217 |
13231035114007 has 2 divisors, whose sum is σ = 13231035114008. Its totient is φ = 13231035114006.
The previous prime is 13231035113927. The next prime is 13231035114023. The reversal of 13231035114007 is 70041153013231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13231035114007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13231035114007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231035114707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615517557003 + 6615517557004.
It is an arithmetic number, because the mean of its divisors is an integer number (6615517557004).
Almost surely, 213231035114007 is an apocalyptic number.
13231035114007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231035114007 is an equidigital number, since it uses as much as digits as its factorization.
13231035114007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 13231035114007 its reverse (70041153013231), we get a palindrome (83272188127238).
The spelling of 13231035114007 in words is "thirteen trillion, two hundred thirty-one billion, thirty-five million, one hundred fourteen thousand, seven".
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