Base | Representation |
---|---|
bin | 10011010000001111000… |
… | …111010110001101101111 |
3 | 11200111011100200102202211 |
4 | 103100033013112031233 |
5 | 133134203444331112 |
6 | 2451454140031251 |
7 | 164406511166446 |
oct | 23201707261557 |
9 | 4614140612684 |
10 | 1323103511407 |
11 | 470141491277 |
12 | 194514832527 |
13 | 979ca759452 |
14 | 48077addd5d |
15 | 2463c3800a7 |
hex | 1340f1d636f |
1323103511407 has 2 divisors, whose sum is σ = 1323103511408. Its totient is φ = 1323103511406.
The previous prime is 1323103511381. The next prime is 1323103511447. The reversal of 1323103511407 is 7041153013231.
It is a weak prime.
It is an emirp because it is prime and its reverse (7041153013231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1323103511407 - 223 = 1323095122799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323103511447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661551755703 + 661551755704.
It is an arithmetic number, because the mean of its divisors is an integer number (661551755704).
Almost surely, 21323103511407 is an apocalyptic number.
1323103511407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323103511407 is an equidigital number, since it uses as much as digits as its factorization.
1323103511407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1323103511407 its reverse (7041153013231), we get a palindrome (8364256524638).
The spelling of 1323103511407 in words is "one trillion, three hundred twenty-three billion, one hundred three million, five hundred eleven thousand, four hundred seven".
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