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1323103511407 is a prime number
BaseRepresentation
bin10011010000001111000…
…111010110001101101111
311200111011100200102202211
4103100033013112031233
5133134203444331112
62451454140031251
7164406511166446
oct23201707261557
94614140612684
101323103511407
11470141491277
12194514832527
13979ca759452
1448077addd5d
152463c3800a7
hex1340f1d636f

1323103511407 has 2 divisors, whose sum is σ = 1323103511408. Its totient is φ = 1323103511406.

The previous prime is 1323103511381. The next prime is 1323103511447. The reversal of 1323103511407 is 7041153013231.

It is a weak prime.

It is an emirp because it is prime and its reverse (7041153013231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323103511407 - 223 = 1323095122799 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323103511447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661551755703 + 661551755704.

It is an arithmetic number, because the mean of its divisors is an integer number (661551755704).

Almost surely, 21323103511407 is an apocalyptic number.

1323103511407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323103511407 is an equidigital number, since it uses as much as digits as its factorization.

1323103511407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 1323103511407 its reverse (7041153013231), we get a palindrome (8364256524638).

The spelling of 1323103511407 in words is "one trillion, three hundred twenty-three billion, one hundred three million, five hundred eleven thousand, four hundred seven".