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13231040000 = 2954173239
BaseRepresentation
bin11000101001010000…
…11010011000000000
31021011002112110202112
430110220122120000
5204044121240000
610024523034452
7645606661433
oct142450323000
937132473675
1013231040000
11567a639202
12269306ba28
13132b206469
148d730b81a
1552688d235
hex314a1a600

13231040000 has 200 divisors, whose sum is σ = 33364694880. Its totient is φ = 5239808000.

The previous prime is 13231039993. The next prime is 13231040023. The reversal of 13231040000 is 4013231.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 55359881 + ... + 55360119.

Almost surely, 213231040000 is an apocalyptic number.

13231040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13231040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16682347440).

13231040000 is an abundant number, since it is smaller than the sum of its proper divisors (20133654880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13231040000 is an frugal number, since it uses more digits than its factorization.

13231040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450 (or 419 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 13231040000 its reverse (4013231), we get a palindrome (13235053231).

The spelling of 13231040000 in words is "thirteen billion, two hundred thirty-one million, forty thousand".