Base | Representation |
---|---|
bin | 11110000101011000001110… |
… | …100010110010001100101011 |
3 | 122100110210211112111022121212 |
4 | 132011120032202302030223 |
5 | 114320240420132120412 |
6 | 1145222500504023335 |
7 | 36604104041052122 |
oct | 3605301642621453 |
9 | 570423745438555 |
10 | 132311006520107 |
11 | 39181867926818 |
12 | 12a0a914461b4b |
13 | 58a9b4a01643c |
14 | 2495c5b87aab9 |
15 | 1046aa6161222 |
hex | 78560e8b232b |
132311006520107 has 2 divisors, whose sum is σ = 132311006520108. Its totient is φ = 132311006520106.
The previous prime is 132311006520101. The next prime is 132311006520193. The reversal of 132311006520107 is 701025600113231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132311006520107 is a prime.
It is not a weakly prime, because it can be changed into another prime (132311006520101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155503260053 + 66155503260054.
It is an arithmetic number, because the mean of its divisors is an integer number (66155503260054).
Almost surely, 2132311006520107 is an apocalyptic number.
132311006520107 is a deficient number, since it is larger than the sum of its proper divisors (1).
132311006520107 is an equidigital number, since it uses as much as digits as its factorization.
132311006520107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 132311006520107 its reverse (701025600113231), we get a palindrome (833336606633338).
The spelling of 132311006520107 in words is "one hundred thirty-two trillion, three hundred eleven billion, six million, five hundred twenty thousand, one hundred seven".
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