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132311011330301 is a prime number
BaseRepresentation
bin11110000101011000001110…
…110101001000100011111101
3122100110210211212112200222012
4132011120032311020203331
5114320240422400032201
61145222501155101005
736604104126665036
oct3605301665104375
9570423755480865
10132311011330301
113918186a611791
1212a0a915ba1765
1358a9b4b00b9cb
142495c5c36da8d
151046aa67b15bb
hex78560ed488fd

132311011330301 has 2 divisors, whose sum is σ = 132311011330302. Its totient is φ = 132311011330300.

The previous prime is 132311011330261. The next prime is 132311011330319. The reversal of 132311011330301 is 103033110113231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122715104959225 + 9595906371076 = 11077685^2 + 3097726^2 .

It is an emirp because it is prime and its reverse (103033110113231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132311011330301 - 226 = 132310944221437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132311011332301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155505665150 + 66155505665151.

It is an arithmetic number, because the mean of its divisors is an integer number (66155505665151).

Almost surely, 2132311011330301 is an apocalyptic number.

It is an amenable number.

132311011330301 is a deficient number, since it is larger than the sum of its proper divisors (1).

132311011330301 is an equidigital number, since it uses as much as digits as its factorization.

132311011330301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 132311011330301 its reverse (103033110113231), we get a palindrome (235344121443532).

The spelling of 132311011330301 in words is "one hundred thirty-two trillion, three hundred eleven billion, eleven million, three hundred thirty thousand, three hundred one".