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1323112012433 is a prime number
BaseRepresentation
bin10011010000001111100…
…111110001101010010001
311200111011221200022222122
4103100033213301222101
5133134213133344213
62451455042144025
7164406643354001
oct23201747615221
94614157608878
101323112012433
11470146268212
12194517652015
13979cc444943
1448078cb4001
152463ceadd08
hex1340f9f1a91

1323112012433 has 2 divisors, whose sum is σ = 1323112012434. Its totient is φ = 1323112012432.

The previous prime is 1323112012309. The next prime is 1323112012463. The reversal of 1323112012433 is 3342102113231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1293207919249 + 29904093184 = 1137193^2 + 172928^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323112012433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323112012463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661556006216 + 661556006217.

It is an arithmetic number, because the mean of its divisors is an integer number (661556006217).

Almost surely, 21323112012433 is an apocalyptic number.

It is an amenable number.

1323112012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323112012433 is an equidigital number, since it uses as much as digits as its factorization.

1323112012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1323112012433 its reverse (3342102113231), we get a palindrome (4665214125664).

The spelling of 1323112012433 in words is "one trillion, three hundred twenty-three billion, one hundred twelve million, twelve thousand, four hundred thirty-three".