Base | Representation |
---|---|
bin | 11110000101011000100000… |
… | …000010000100001011000111 |
3 | 122100110211120222121020021021 |
4 | 132011120200002010023013 |
5 | 114320242020240322441 |
6 | 1145222545544532011 |
7 | 36604114233034663 |
oct | 3605304002041307 |
9 | 570424528536237 |
10 | 132311299932871 |
11 | 391819a8511104 |
12 | 12a0a996781007 |
13 | 58a9b95a48b67 |
14 | 2495c888178a3 |
15 | 1046ac1cbd3d1 |
hex | 7856200842c7 |
132311299932871 has 2 divisors, whose sum is σ = 132311299932872. Its totient is φ = 132311299932870.
The previous prime is 132311299932839. The next prime is 132311299932881. The reversal of 132311299932871 is 178239992113231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132311299932871 - 25 = 132311299932839 is a prime.
It is a super-2 number, since 2×1323112999328712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132311299932821) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155649966435 + 66155649966436.
It is an arithmetic number, because the mean of its divisors is an integer number (66155649966436).
Almost surely, 2132311299932871 is an apocalyptic number.
132311299932871 is a deficient number, since it is larger than the sum of its proper divisors (1).
132311299932871 is an equidigital number, since it uses as much as digits as its factorization.
132311299932871 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8817984, while the sum is 61.
The spelling of 132311299932871 in words is "one hundred thirty-two trillion, three hundred eleven billion, two hundred ninety-nine million, nine hundred thirty-two thousand, eight hundred seventy-one".
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