Base | Representation |
---|---|
bin | 11110000101011000100000… |
… | …001010000100001010010111 |
3 | 122100110211121010112202221210 |
4 | 132011120200022010022113 |
5 | 114320242021304424400 |
6 | 1145222550101512503 |
7 | 36604114256620665 |
oct | 3605304012041227 |
9 | 570424533482853 |
10 | 132311302029975 |
11 | 391819a9713752 |
12 | 12a0a997412733 |
13 | 58a9b96301553 |
14 | 2495c88c01c35 |
15 | 1046ac2084950 |
hex | 785620284297 |
132311302029975 has 48 divisors (see below), whose sum is σ = 220145236624512. Its totient is φ = 70117653836160.
The previous prime is 132311302029971. The next prime is 132311302029997. The reversal of 132311302029975 is 579920203113231.
It is not a de Polignac number, because 132311302029975 - 22 = 132311302029971 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132311302029971) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 54396949 + ... + 56777201.
It is an arithmetic number, because the mean of its divisors is an integer number (4586359096344).
Almost surely, 2132311302029975 is an apocalyptic number.
132311302029975 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132311302029975 is a deficient number, since it is larger than the sum of its proper divisors (87833934594537).
132311302029975 is a wasteful number, since it uses less digits than its factorization.
132311302029975 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2384976 (or 2384971 counting only the distinct ones).
The product of its (nonzero) digits is 612360, while the sum is 48.
The spelling of 132311302029975 in words is "one hundred thirty-two trillion, three hundred eleven billion, three hundred two million, twenty-nine thousand, nine hundred seventy-five".
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