Base | Representation |
---|---|
bin | 1100000010001001110011… |
… | …1100101011101101010010 |
3 | 1201211212212100221021021020 |
4 | 3000202130330223231102 |
5 | 3213234324400100132 |
6 | 44050144234340310 |
7 | 2533626536656110 |
oct | 300423474535522 |
9 | 51755770837236 |
10 | 13231132425042 |
11 | 4241323356694 |
12 | 159834758a696 |
13 | 74c8c8b6406c |
14 | 33a566ad0ab0 |
15 | 17e28ad7352c |
hex | c089cf2bb52 |
13231132425042 has 32 divisors (see below), whose sum is σ = 30242835014784. Its totient is φ = 3780292723200.
The previous prime is 13231132425019. The next prime is 13231132425047. The reversal of 13231132425042 is 24052423113231.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 13231132424994 and 13231132425012.
It is not an unprimeable number, because it can be changed into a prime (13231132425047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4203192 + ... + 6642972.
It is an arithmetic number, because the mean of its divisors is an integer number (945088594212).
Almost surely, 213231132425042 is an apocalyptic number.
13231132425042 is an abundant number, since it is smaller than the sum of its proper divisors (17011702589742).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13231132425042 is a wasteful number, since it uses less digits than its factorization.
13231132425042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2568914.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13231132425042 its reverse (24052423113231), we get a palindrome (37283555538273).
The spelling of 13231132425042 in words is "thirteen trillion, two hundred thirty-one billion, one hundred thirty-two million, four hundred twenty-five thousand, forty-two".
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