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1323121451 is a prime number
BaseRepresentation
bin100111011011101…
…0011101100101011
310102012200112102012
41032313103230223
510202204341301
6335143030135
744534226641
oct11667235453
93365615365
101323121451
1161995a803
1230b13b34b
13181172102
14c7a1d191
157b25aebb
hex4edd3b2b

1323121451 has 2 divisors, whose sum is σ = 1323121452. Its totient is φ = 1323121450.

The previous prime is 1323121439. The next prime is 1323121453. The reversal of 1323121451 is 1541213231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1323121451 - 210 = 1323120427 is a prime.

Together with 1323121453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1323121453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661560725 + 661560726.

It is an arithmetic number, because the mean of its divisors is an integer number (661560726).

Almost surely, 21323121451 is an apocalyptic number.

1323121451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323121451 is an equidigital number, since it uses as much as digits as its factorization.

1323121451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 23.

The square root of 1323121451 is about 36374.7364389077. The cubic root of 1323121451 is about 1097.8253042948.

Adding to 1323121451 its reverse (1541213231), we get a palindrome (2864334682).

The spelling of 1323121451 in words is "one billion, three hundred twenty-three million, one hundred twenty-one thousand, four hundred fifty-one".