Base | Representation |
---|---|
bin | 10011010000010000101… |
… | …101001110111010110101 |
3 | 11200111020012221101100212 |
4 | 103100100231032322311 |
5 | 133134232314021323 |
6 | 2451500532315205 |
7 | 164410254206624 |
oct | 23202055167265 |
9 | 4614205841325 |
10 | 1323130220213 |
11 | 470155573a6a |
12 | 194521772b05 |
13 | 97a0314b389 |
14 | 4807b4936bb |
15 | 2463e8a8b78 |
hex | 13410b4eeb5 |
1323130220213 has 2 divisors, whose sum is σ = 1323130220214. Its totient is φ = 1323130220212.
The previous prime is 1323130220189. The next prime is 1323130220233. The reversal of 1323130220213 is 3120220313231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 839572703524 + 483557516689 = 916282^2 + 695383^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323130220213 - 210 = 1323130219189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323130220233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661565110106 + 661565110107.
It is an arithmetic number, because the mean of its divisors is an integer number (661565110107).
Almost surely, 21323130220213 is an apocalyptic number.
It is an amenable number.
1323130220213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323130220213 is an equidigital number, since it uses as much as digits as its factorization.
1323130220213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1323130220213 its reverse (3120220313231), we get a palindrome (4443350533444).
The spelling of 1323130220213 in words is "one trillion, three hundred twenty-three billion, one hundred thirty million, two hundred twenty thousand, two hundred thirteen".
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