Base | Representation |
---|---|
bin | 1100000010001010011110… |
… | …1110101101101000101111 |
3 | 1201211220022222022021221102 |
4 | 3000202213232231220233 |
5 | 3213240212201443203 |
6 | 44050214215353315 |
7 | 2533634164331162 |
oct | 300424756555057 |
9 | 51756288267842 |
10 | 13231313312303 |
11 | 4241406474999 |
12 | 159839808283b |
13 | 74c927488a48 |
14 | 33a582b39ad9 |
15 | 17e29bba4888 |
hex | c08a7bada2f |
13231313312303 has 2 divisors, whose sum is σ = 13231313312304. Its totient is φ = 13231313312302.
The previous prime is 13231313312179. The next prime is 13231313312359. The reversal of 13231313312303 is 30321331313231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231313312303 - 218 = 13231313050159 is a prime.
It is a super-2 number, since 2×132313133123032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231313312383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615656656151 + 6615656656152.
It is an arithmetic number, because the mean of its divisors is an integer number (6615656656152).
Almost surely, 213231313312303 is an apocalyptic number.
13231313312303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231313312303 is an equidigital number, since it uses as much as digits as its factorization.
13231313312303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8748, while the sum is 29.
Adding to 13231313312303 its reverse (30321331313231), we get a palindrome (43552644625534).
The spelling of 13231313312303 in words is "thirteen trillion, two hundred thirty-one billion, three hundred thirteen million, three hundred twelve thousand, three hundred three".
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