Base | Representation |
---|---|
bin | 111101100111010001… |
… | …1100000011001001100 |
3 | 110122112012221121222021 |
4 | 1323032203200121030 |
5 | 4131434443324400 |
6 | 140441233255524 |
7 | 12362606060503 |
oct | 1731643403114 |
9 | 418465847867 |
10 | 132314433100 |
11 | 51129058a63 |
12 | 21787a045a4 |
13 | c628531285 |
14 | 6592a1383a |
15 | 369613671a |
hex | 1ece8e064c |
132314433100 has 72 divisors (see below), whose sum is σ = 288089005568. Its totient is φ = 52747891200.
The previous prime is 132314433049. The next prime is 132314433103. The reversal of 132314433100 is 1334413231.
It is a super-2 number, since 2×1323144331002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (132314433103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 75998230 + ... + 75999970.
Almost surely, 2132314433100 is an apocalyptic number.
132314433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132314433100 is an abundant number, since it is smaller than the sum of its proper divisors (155774572468).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132314433100 is a wasteful number, since it uses less digits than its factorization.
132314433100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3875 (or 3868 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 132314433100 its reverse (1334413231), we get a palindrome (133648846331).
The spelling of 132314433100 in words is "one hundred thirty-two billion, three hundred fourteen million, four hundred thirty-three thousand, one hundred".
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