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13231450415531 is a prime number
BaseRepresentation
bin1100000010001010111111…
…1001101110000110101011
31201211220200112021212012202
43000202233321232012223
53213241002301244111
644050235554130415
72533640450565065
oct300425771560653
951756615255182
1013231450415531
1142414768a8647
121598415b80a0b
1374c9499c070a
1433a597028735
1517e2a8c37b3b
hexc08afe6e1ab

13231450415531 has 2 divisors, whose sum is σ = 13231450415532. Its totient is φ = 13231450415530.

The previous prime is 13231450415473. The next prime is 13231450415537. The reversal of 13231450415531 is 13551405413231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13231450415531 is a prime.

It is a super-2 number, since 2×132314504155312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13231450415537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615725207765 + 6615725207766.

It is an arithmetic number, because the mean of its divisors is an integer number (6615725207766).

Almost surely, 213231450415531 is an apocalyptic number.

13231450415531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13231450415531 is an equidigital number, since it uses as much as digits as its factorization.

13231450415531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 13231450415531 its reverse (13551405413231), we get a palindrome (26782855828762).

The spelling of 13231450415531 in words is "thirteen trillion, two hundred thirty-one billion, four hundred fifty million, four hundred fifteen thousand, five hundred thirty-one".