Base | Representation |
---|---|
bin | 111101100111010001… |
… | …1110110110110111101 |
3 | 110122112020010022012022 |
4 | 1323032203312312331 |
5 | 4131440004300432 |
6 | 140441235245525 |
7 | 12362606622665 |
oct | 1731643666675 |
9 | 418466108168 |
10 | 132314525117 |
11 | 51129111105 |
12 | 21787a498a5 |
13 | c628564118 |
14 | 6592a391a5 |
15 | 3696153b12 |
hex | 1ece8f6dbd |
132314525117 has 2 divisors, whose sum is σ = 132314525118. Its totient is φ = 132314525116.
The previous prime is 132314525107. The next prime is 132314525149. The reversal of 132314525117 is 711525413231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80150705881 + 52163819236 = 283109^2 + 228394^2 .
It is a cyclic number.
It is not a de Polignac number, because 132314525117 - 220 = 132313476541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132314525107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157262558 + 66157262559.
It is an arithmetic number, because the mean of its divisors is an integer number (66157262559).
Almost surely, 2132314525117 is an apocalyptic number.
It is an amenable number.
132314525117 is a deficient number, since it is larger than the sum of its proper divisors (1).
132314525117 is an equidigital number, since it uses as much as digits as its factorization.
132314525117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25200, while the sum is 35.
Adding to 132314525117 its reverse (711525413231), we get a palindrome (843839938348).
The spelling of 132314525117 in words is "one hundred thirty-two billion, three hundred fourteen million, five hundred twenty-five thousand, one hundred seventeen".
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