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132314525117 is a prime number
BaseRepresentation
bin111101100111010001…
…1110110110110111101
3110122112020010022012022
41323032203312312331
54131440004300432
6140441235245525
712362606622665
oct1731643666675
9418466108168
10132314525117
1151129111105
1221787a498a5
13c628564118
146592a391a5
153696153b12
hex1ece8f6dbd

132314525117 has 2 divisors, whose sum is σ = 132314525118. Its totient is φ = 132314525116.

The previous prime is 132314525107. The next prime is 132314525149. The reversal of 132314525117 is 711525413231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80150705881 + 52163819236 = 283109^2 + 228394^2 .

It is a cyclic number.

It is not a de Polignac number, because 132314525117 - 220 = 132313476541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132314525107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157262558 + 66157262559.

It is an arithmetic number, because the mean of its divisors is an integer number (66157262559).

Almost surely, 2132314525117 is an apocalyptic number.

It is an amenable number.

132314525117 is a deficient number, since it is larger than the sum of its proper divisors (1).

132314525117 is an equidigital number, since it uses as much as digits as its factorization.

132314525117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25200, while the sum is 35.

Adding to 132314525117 its reverse (711525413231), we get a palindrome (843839938348).

The spelling of 132314525117 in words is "one hundred thirty-two billion, three hundred fourteen million, five hundred twenty-five thousand, one hundred seventeen".