Base | Representation |
---|---|
bin | 11110000101011100001001… |
… | …110101000110110101011111 |
3 | 122100111012201100102102201022 |
4 | 132011130021311012311133 |
5 | 114320323033413420242 |
6 | 1145224435105034355 |
7 | 36604313362351115 |
oct | 3605341165066537 |
9 | 570435640372638 |
10 | 132315222404447 |
11 | 39183630662055 |
12 | 12a0b6b03259bb |
13 | 58aa36c594164 |
14 | 249613b749ab5 |
15 | 1046c5132c0d2 |
hex | 785709d46d5f |
132315222404447 has 2 divisors, whose sum is σ = 132315222404448. Its totient is φ = 132315222404446.
The previous prime is 132315222404357. The next prime is 132315222404467. The reversal of 132315222404447 is 744404222513231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132315222404447 - 220 = 132315221355871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132315222404398 and 132315222404407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132315222404467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157611202223 + 66157611202224.
It is an arithmetic number, because the mean of its divisors is an integer number (66157611202224).
Almost surely, 2132315222404447 is an apocalyptic number.
132315222404447 is a deficient number, since it is larger than the sum of its proper divisors (1).
132315222404447 is an equidigital number, since it uses as much as digits as its factorization.
132315222404447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1290240, while the sum is 44.
Adding to 132315222404447 its reverse (744404222513231), we get a palindrome (876719444917678).
The spelling of 132315222404447 in words is "one hundred thirty-two trillion, three hundred fifteen billion, two hundred twenty-two million, four hundred four thousand, four hundred forty-seven".
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