Base | Representation |
---|---|
bin | 11110000101011100011101… |
… | …100110001010011011110011 |
3 | 122100111020120110102211022002 |
4 | 132011130131212022123303 |
5 | 114320324223313000342 |
6 | 1145224532033004215 |
7 | 36604324530213311 |
oct | 3605343546123363 |
9 | 570436513384262 |
10 | 132315554031347 |
11 | 39183790878275 |
12 | 12a0b7833b366b |
13 | 58aa3c31b65ab |
14 | 249616d7d30b1 |
15 | 1046c704d6d32 |
hex | 78571d98a6f3 |
132315554031347 has 2 divisors, whose sum is σ = 132315554031348. Its totient is φ = 132315554031346.
The previous prime is 132315554031257. The next prime is 132315554031377. The reversal of 132315554031347 is 743130455513231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132315554031347 is a prime.
It is not a weakly prime, because it can be changed into another prime (132315554031377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157777015673 + 66157777015674.
It is an arithmetic number, because the mean of its divisors is an integer number (66157777015674).
Almost surely, 2132315554031347 is an apocalyptic number.
132315554031347 is a deficient number, since it is larger than the sum of its proper divisors (1).
132315554031347 is an equidigital number, since it uses as much as digits as its factorization.
132315554031347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268000, while the sum is 47.
The spelling of 132315554031347 in words is "one hundred thirty-two trillion, three hundred fifteen billion, five hundred fifty-four million, thirty-one thousand, three hundred forty-seven".
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