Base | Representation |
---|---|
bin | 11110000101100000100111… |
… | …010001101011001110110111 |
3 | 122100111200002002202121202101 |
4 | 132011200213101223032313 |
5 | 114320412340404300434 |
6 | 1145230550221522531 |
7 | 36604543143216454 |
oct | 3605404721531667 |
9 | 570450062677671 |
10 | 132320011400119 |
11 | 39185668950414 |
12 | 12a10608113447 |
13 | 58aa9537b49ca |
14 | 24964737a282b |
15 | 1046e319a3b14 |
hex | 78582746b3b7 |
132320011400119 has 2 divisors, whose sum is σ = 132320011400120. Its totient is φ = 132320011400118.
The previous prime is 132320011400107. The next prime is 132320011400237. The reversal of 132320011400119 is 911004110023231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132320011400119 - 27 = 132320011399991 is a prime.
It is a super-2 number, since 2×1323200114001192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132320011400719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160005700059 + 66160005700060.
It is an arithmetic number, because the mean of its divisors is an integer number (66160005700060).
Almost surely, 2132320011400119 is an apocalyptic number.
132320011400119 is a deficient number, since it is larger than the sum of its proper divisors (1).
132320011400119 is an equidigital number, since it uses as much as digits as its factorization.
132320011400119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 132320011400119 in words is "one hundred thirty-two trillion, three hundred twenty billion, eleven million, four hundred thousand, one hundred nineteen".
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