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132320314323193 is a prime number
BaseRepresentation
bin11110000101100000111001…
…010101001111000011111001
3122100111200212012202201002111
4132011200321111033003321
5114320414000431320233
61145231040242332321
736604553512062223
oct3605407125170371
9570450765681074
10132320314323193
1139185803940a67
1212a1069165a0a1
1358aa9a1497129
1424964a1ad7413
151046e4d38dacd
hex78583954f0f9

132320314323193 has 2 divisors, whose sum is σ = 132320314323194. Its totient is φ = 132320314323192.

The previous prime is 132320314323167. The next prime is 132320314323287. The reversal of 132320314323193 is 391323413023231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124603013655184 + 7717300668009 = 11162572^2 + 2778003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132320314323193 is a prime.

It is not a weakly prime, because it can be changed into another prime (132320314321193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160157161596 + 66160157161597.

It is an arithmetic number, because the mean of its divisors is an integer number (66160157161597).

Almost surely, 2132320314323193 is an apocalyptic number.

It is an amenable number.

132320314323193 is a deficient number, since it is larger than the sum of its proper divisors (1).

132320314323193 is an equidigital number, since it uses as much as digits as its factorization.

132320314323193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 40.

The spelling of 132320314323193 in words is "one hundred thirty-two trillion, three hundred twenty billion, three hundred fourteen million, three hundred twenty-three thousand, one hundred ninety-three".