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132320314323167 is a prime number
BaseRepresentation
bin11110000101100000111001…
…010101001111000011011111
3122100111200212012202201001112
4132011200321111033003133
5114320414000431320132
61145231040242332235
736604553512062155
oct3605407125170337
9570450765681045
10132320314323167
1139185803940a43
1212a1069165a07b
1358aa9a1497109
1424964a1ad73d5
151046e4d38dab2
hex78583954f0df

132320314323167 has 2 divisors, whose sum is σ = 132320314323168. Its totient is φ = 132320314323166.

The previous prime is 132320314323157. The next prime is 132320314323193. The reversal of 132320314323167 is 761323413023231.

It is a weak prime.

It is an emirp because it is prime and its reverse (761323413023231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132320314323167 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132320314323157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160157161583 + 66160157161584.

It is an arithmetic number, because the mean of its divisors is an integer number (66160157161584).

Almost surely, 2132320314323167 is an apocalyptic number.

132320314323167 is a deficient number, since it is larger than the sum of its proper divisors (1).

132320314323167 is an equidigital number, since it uses as much as digits as its factorization.

132320314323167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 41.

Adding to 132320314323167 its reverse (761323413023231), we get a palindrome (893643727346398).

The spelling of 132320314323167 in words is "one hundred thirty-two trillion, three hundred twenty billion, three hundred fourteen million, three hundred twenty-three thousand, one hundred sixty-seven".