Base | Representation |
---|---|
bin | 10011010000010101011… |
… | …101100100011111000011 |
3 | 11200111102210001122002202 |
4 | 103100111131210133003 |
5 | 133134413230002243 |
6 | 2451512502303415 |
7 | 164412243265661 |
oct | 23202535443703 |
9 | 4614383048082 |
10 | 1323210000323 |
11 | 470196604a42 |
12 | 194544427b6b |
13 | 97a16832643 |
14 | 48087cddc31 |
15 | 246468b74b8 |
hex | 134157647c3 |
1323210000323 has 2 divisors, whose sum is σ = 1323210000324. Its totient is φ = 1323210000322.
The previous prime is 1323210000311. The next prime is 1323210000331. The reversal of 1323210000323 is 3230000123231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1323210000323 - 28 = 1323210000067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1323210000295 and 1323210000304.
It is not a weakly prime, because it can be changed into another prime (1323210000373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661605000161 + 661605000162.
It is an arithmetic number, because the mean of its divisors is an integer number (661605000162).
Almost surely, 21323210000323 is an apocalyptic number.
1323210000323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323210000323 is an equidigital number, since it uses as much as digits as its factorization.
1323210000323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 1323210000323 its reverse (3230000123231), we get a palindrome (4553210123554).
The spelling of 1323210000323 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, three hundred twenty-three", and thus it is an aban number.
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