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1323210000331 is a prime number
BaseRepresentation
bin10011010000010101011…
…101100100011111001011
311200111102210001122010001
4103100111131210133023
5133134413230002311
62451512502303431
7164412243266002
oct23202535443713
94614383048101
101323210000331
11470196604a4a
12194544427b77
1397a1683264b
1448087cddc39
15246468b74c1
hex134157647cb

1323210000331 has 2 divisors, whose sum is σ = 1323210000332. Its totient is φ = 1323210000330.

The previous prime is 1323210000323. The next prime is 1323210000337. The reversal of 1323210000331 is 1330000123231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1323210000331 - 23 = 1323210000323 is a prime.

It is a super-2 number, since 2×13232100003312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1323210000299 and 1323210000308.

It is not a weakly prime, because it can be changed into another prime (1323210000337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661605000165 + 661605000166.

It is an arithmetic number, because the mean of its divisors is an integer number (661605000166).

Almost surely, 21323210000331 is an apocalyptic number.

1323210000331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323210000331 is an equidigital number, since it uses as much as digits as its factorization.

1323210000331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1323210000331 its reverse (1330000123231), we get a palindrome (2653210123562).

The spelling of 1323210000331 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, three hundred thirty-one", and thus it is an aban number.