Base | Representation |
---|---|
bin | 111101100111011110… |
… | …1110000001001111011 |
3 | 110122112200220011222022 |
4 | 1323032331300021323 |
5 | 4131443224012103 |
6 | 140442040545055 |
7 | 12363021414626 |
oct | 1731675601173 |
9 | 418480804868 |
10 | 132321313403 |
11 | 51131a28264 |
12 | 2178a18218b |
13 | c629a9cb66 |
14 | 65938c4dbd |
15 | 3696a45138 |
hex | 1ecef7027b |
132321313403 has 2 divisors, whose sum is σ = 132321313404. Its totient is φ = 132321313402.
The previous prime is 132321313379. The next prime is 132321313427. The reversal of 132321313403 is 304313123231.
It is a balanced prime because it is at equal distance from previous prime (132321313379) and next prime (132321313427).
It is a cyclic number.
It is not a de Polignac number, because 132321313403 - 210 = 132321312379 is a prime.
It is not a weakly prime, because it can be changed into another prime (132321313463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160656701 + 66160656702.
It is an arithmetic number, because the mean of its divisors is an integer number (66160656702).
Almost surely, 2132321313403 is an apocalyptic number.
132321313403 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321313403 is an equidigital number, since it uses as much as digits as its factorization.
132321313403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 132321313403 its reverse (304313123231), we get a palindrome (436634436634).
The spelling of 132321313403 in words is "one hundred thirty-two billion, three hundred twenty-one million, three hundred thirteen thousand, four hundred three".
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