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1323213200233 is a prime number
BaseRepresentation
bin10011010000010101101…
…001110001101101101001
311200111110000002012112221
4103100111221301231221
5133134420034401413
62451513055034041
7164412312424111
oct23202551615551
94614400065487
101323213200233
114701983a00a1
1219454550b921
1397a173b2c92
14480884d4041
1524646cea68d
hex13415a71b69

1323213200233 has 2 divisors, whose sum is σ = 1323213200234. Its totient is φ = 1323213200232.

The previous prime is 1323213200203. The next prime is 1323213200237. The reversal of 1323213200233 is 3320023123231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1188954713664 + 134258486569 = 1090392^2 + 366413^2 .

It is an emirp because it is prime and its reverse (3320023123231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323213200233 - 25 = 1323213200201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1323213200198 and 1323213200207.

It is not a weakly prime, because it can be changed into another prime (1323213200237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661606600116 + 661606600117.

It is an arithmetic number, because the mean of its divisors is an integer number (661606600117).

Almost surely, 21323213200233 is an apocalyptic number.

It is an amenable number.

1323213200233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323213200233 is an equidigital number, since it uses as much as digits as its factorization.

1323213200233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1323213200233 its reverse (3320023123231), we get a palindrome (4643236323464).

The spelling of 1323213200233 in words is "one trillion, three hundred twenty-three billion, two hundred thirteen million, two hundred thousand, two hundred thirty-three".