Base | Representation |
---|---|
bin | 11110000101100010100000… |
… | …001100010000100101111111 |
3 | 122100111212022110222100202211 |
4 | 132011202200030100211333 |
5 | 114320431014221222143 |
6 | 1145231523410201251 |
7 | 36604644335224225 |
oct | 3605424014204577 |
9 | 570455273870684 |
10 | 132322040023423 |
11 | 39186509a680a8 |
12 | 12a10a93583227 |
13 | 58aabb7b71523 |
14 | 24965c6d8cb15 |
15 | 1046eeeb1c49d |
hex | 7858a031097f |
132322040023423 has 2 divisors, whose sum is σ = 132322040023424. Its totient is φ = 132322040023422.
The previous prime is 132322040023403. The next prime is 132322040023427. The reversal of 132322040023423 is 324320040223231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132322040023423 - 241 = 130123016767871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132322040023427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66161020011711 + 66161020011712.
It is an arithmetic number, because the mean of its divisors is an integer number (66161020011712).
Almost surely, 2132322040023423 is an apocalyptic number.
132322040023423 is a deficient number, since it is larger than the sum of its proper divisors (1).
132322040023423 is an equidigital number, since it uses as much as digits as its factorization.
132322040023423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 132322040023423 its reverse (324320040223231), we get a palindrome (456642080246654).
The spelling of 132322040023423 in words is "one hundred thirty-two trillion, three hundred twenty-two billion, forty million, twenty-three thousand, four hundred twenty-three".
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