Base | Representation |
---|---|
bin | 111101100111100000… |
… | …1100100010010111001 |
3 | 110122112202202222201021 |
4 | 1323033001210102321 |
5 | 4131444003012101 |
6 | 140442114222441 |
7 | 12363033051235 |
oct | 1731701442271 |
9 | 418482688637 |
10 | 132322313401 |
11 | 51132550603 |
12 | 2178a584a21 |
13 | c62a060085 |
14 | 6593aa55c5 |
15 | 3696b915a1 |
hex | 1ecf0644b9 |
132322313401 has 2 divisors, whose sum is σ = 132322313402. Its totient is φ = 132322313400.
The previous prime is 132322313369. The next prime is 132322313533. The reversal of 132322313401 is 104313223231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 132222413376 + 99900025 = 363624^2 + 9995^2 .
It is a cyclic number.
It is not a de Polignac number, because 132322313401 - 25 = 132322313369 is a prime.
It is not a weakly prime, because it can be changed into another prime (132322413401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66161156700 + 66161156701.
It is an arithmetic number, because the mean of its divisors is an integer number (66161156701).
Almost surely, 2132322313401 is an apocalyptic number.
It is an amenable number.
132322313401 is a deficient number, since it is larger than the sum of its proper divisors (1).
132322313401 is an equidigital number, since it uses as much as digits as its factorization.
132322313401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 132322313401 its reverse (104313223231), we get a palindrome (236635536632).
The spelling of 132322313401 in words is "one hundred thirty-two billion, three hundred twenty-two million, three hundred thirteen thousand, four hundred one".
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