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132323207 is a prime number
BaseRepresentation
bin1111110001100…
…01011110000111
3100012222201022112
413320301132013
5232333320312
621044051235
73164504642
oct770613607
9305881275
10132323207
1168769425
1238393b1b
1321550073
1413806a59
15b93bd22
hex7e31787

132323207 has 2 divisors, whose sum is σ = 132323208. Its totient is φ = 132323206.

The previous prime is 132323179. The next prime is 132323227. The reversal of 132323207 is 702323231.

It is a strong prime.

It is an emirp because it is prime and its reverse (702323231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132323207 - 218 = 132061063 is a prime.

It is a super-2 number, since 2×1323232072 = 35018862221529698, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132323227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66161603 + 66161604.

It is an arithmetic number, because the mean of its divisors is an integer number (66161604).

Almost surely, 2132323207 is an apocalyptic number.

132323207 is a deficient number, since it is larger than the sum of its proper divisors (1).

132323207 is an equidigital number, since it uses as much as digits as its factorization.

132323207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 23.

The square root of 132323207 is about 11503.1824726899. The cubic root of 132323207 is about 509.5795676360.

Adding to 132323207 its reverse (702323231), we get a palindrome (834646438).

The spelling of 132323207 in words is "one hundred thirty-two million, three hundred twenty-three thousand, two hundred seven".