Base | Representation |
---|---|
bin | 11000101001011011… |
… | …01001001001100001 |
3 | 1021011012010010201221 |
4 | 30110231221021201 |
5 | 204044444124413 |
6 | 10025012255041 |
7 | 645624432256 |
oct | 142455511141 |
9 | 37135103657 |
10 | 13232411233 |
11 | 5680395458 |
12 | 2693611481 |
13 | 132b596642 |
14 | 8d758742d |
15 | 526a5e68d |
hex | 314b69261 |
13232411233 has 2 divisors, whose sum is σ = 13232411234. Its totient is φ = 13232411232.
The previous prime is 13232411197. The next prime is 13232411237. The reversal of 13232411233 is 33211423231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11787879184 + 1444532049 = 108572^2 + 38007^2 .
It is a cyclic number.
It is not a de Polignac number, because 13232411233 - 217 = 13232280161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13232411198 and 13232411207.
It is not a weakly prime, because it can be changed into another prime (13232411237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616205616 + 6616205617.
It is an arithmetic number, because the mean of its divisors is an integer number (6616205617).
Almost surely, 213232411233 is an apocalyptic number.
It is an amenable number.
13232411233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232411233 is an equidigital number, since it uses as much as digits as its factorization.
13232411233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 25.
Adding to 13232411233 its reverse (33211423231), we get a palindrome (46443834464).
The spelling of 13232411233 in words is "thirteen billion, two hundred thirty-two million, four hundred eleven thousand, two hundred thirty-three".
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