132331312647050 has 48 divisors (see below), whose sum is σ = 268513474975200. Its totient is φ = 48120260212800.

The previous prime is 132331312647019. The next prime is 132331312647073. The reversal of 132331312647050 is 50746213133231.

It is a super-3 number, since 3×132331312647050³ (a number of 43 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 132331312646989 and 132331312647007.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 170320856 + ... + 171096044.

It is an arithmetic number, because the mean of its divisors is an integer number (5594030728650).

Almost surely, 2^{132331312647050} is an apocalyptic number.

132331312647050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

132331312647050 is an abundant number, since it is smaller than the sum of its proper divisors (136182162328150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132331312647050 is a wasteful number, since it uses less digits than its factorization.

132331312647050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1085591 (or 1085586 counting only the distinct ones).

The product of its (nonzero) digits is 272160, while the sum is 41.

The spelling of 132331312647050 in words is "one hundred thirty-two trillion, three hundred thirty-one billion, three hundred twelve million, six hundred forty-seven thousand, fifty".