Base | Representation |
---|---|
bin | 1100000010010001010101… |
… | …0100110111011101000011 |
3 | 1201212002002010011212011112 |
4 | 3000210111110313131003 |
5 | 3213302443404434111 |
6 | 44051120501433535 |
7 | 2534030562224546 |
oct | 300442524673503 |
9 | 51762063155145 |
10 | 13233152030531 |
11 | 424216a374134 |
12 | 159880ba0b8ab |
13 | 74cb5b3b40b4 |
14 | 33a6b901085d |
15 | 17e358309e8b |
hex | c0915537743 |
13233152030531 has 2 divisors, whose sum is σ = 13233152030532. Its totient is φ = 13233152030530.
The previous prime is 13233152030491. The next prime is 13233152030591. The reversal of 13233152030531 is 13503025133231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13233152030531 - 218 = 13233151768387 is a prime.
It is a super-2 number, since 2×132331520305312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13233152030591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616576015265 + 6616576015266.
It is an arithmetic number, because the mean of its divisors is an integer number (6616576015266).
Almost surely, 213233152030531 is an apocalyptic number.
13233152030531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13233152030531 is an equidigital number, since it uses as much as digits as its factorization.
13233152030531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 32.
Adding to 13233152030531 its reverse (13503025133231), we get a palindrome (26736177163762).
The spelling of 13233152030531 in words is "thirteen trillion, two hundred thirty-three billion, one hundred fifty-two million, thirty thousand, five hundred thirty-one".
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