Base | Representation |
---|---|
bin | 111101100111110011… |
… | …0111101000011000001 |
3 | 110122120110012220202121 |
4 | 1323033212331003001 |
5 | 4132004010122423 |
6 | 140443104244241 |
7 | 12363212260603 |
oct | 1731746750301 |
9 | 418513186677 |
10 | 132332114113 |
11 | 51138034a71 |
12 | 21791910681 |
13 | c62c0b2004 |
14 | 65950d7173 |
15 | 369797a45d |
hex | 1ecf9bd0c1 |
132332114113 has 2 divisors, whose sum is σ = 132332114114. Its totient is φ = 132332114112.
The previous prime is 132332114093. The next prime is 132332114183. The reversal of 132332114113 is 311411233231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102031052929 + 30301061184 = 319423^2 + 174072^2 .
It is a cyclic number.
It is not a de Polignac number, because 132332114113 - 225 = 132298559681 is a prime.
It is not a weakly prime, because it can be changed into another prime (132332114183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66166057056 + 66166057057.
It is an arithmetic number, because the mean of its divisors is an integer number (66166057057).
Almost surely, 2132332114113 is an apocalyptic number.
It is an amenable number.
132332114113 is a deficient number, since it is larger than the sum of its proper divisors (1).
132332114113 is an equidigital number, since it uses as much as digits as its factorization.
132332114113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 25.
Adding to 132332114113 its reverse (311411233231), we get a palindrome (443743347344).
The spelling of 132332114113 in words is "one hundred thirty-two billion, three hundred thirty-two million, one hundred fourteen thousand, one hundred thirteen".
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