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1323321212113 is a prime number
BaseRepresentation
bin10011010000011100000…
…101110011110011010001
311200111201112022202222221
4103100130011303303101
5133140130212241423
62451531514101041
7164415063465415
oct23203405636321
94614645282887
101323321212113
1147024336400a
1219457571a781
1397a338a0434
14480989acd45
1524651533e5d
hex1341c173cd1

1323321212113 has 2 divisors, whose sum is σ = 1323321212114. Its totient is φ = 1323321212112.

The previous prime is 1323321212077. The next prime is 1323321212153. The reversal of 1323321212113 is 3112121233231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1323263710224 + 57501889 = 1150332^2 + 7583^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323321212113 - 29 = 1323321211601 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323321212153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661660606056 + 661660606057.

It is an arithmetic number, because the mean of its divisors is an integer number (661660606057).

Almost surely, 21323321212113 is an apocalyptic number.

It is an amenable number.

1323321212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323321212113 is an equidigital number, since it uses as much as digits as its factorization.

1323321212113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 25.

Adding to 1323321212113 its reverse (3112121233231), we get a palindrome (4435442445344).

The spelling of 1323321212113 in words is "one trillion, three hundred twenty-three billion, three hundred twenty-one million, two hundred twelve thousand, one hundred thirteen".