Base | Representation |
---|---|
bin | 111101100111110011… |
… | …1010110111011011111 |
3 | 110122120110102022012001 |
4 | 1323033213112323133 |
5 | 4132004022021002 |
6 | 140443110423131 |
7 | 12363213211642 |
oct | 1731747267337 |
9 | 418513368161 |
10 | 132332220127 |
11 | 511380a7688 |
12 | 21791961aa7 |
13 | c62c11b343 |
14 | 6595123a59 |
15 | 369799ba87 |
hex | 1ecf9d6edf |
132332220127 has 2 divisors, whose sum is σ = 132332220128. Its totient is φ = 132332220126.
The previous prime is 132332220071. The next prime is 132332220149. The reversal of 132332220127 is 721022233231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132332220127 - 211 = 132332218079 is a prime.
It is a super-2 number, since 2×1323322201272 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132332220095 and 132332220104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132332220197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66166110063 + 66166110064.
It is an arithmetic number, because the mean of its divisors is an integer number (66166110064).
Almost surely, 2132332220127 is an apocalyptic number.
132332220127 is a deficient number, since it is larger than the sum of its proper divisors (1).
132332220127 is an equidigital number, since it uses as much as digits as its factorization.
132332220127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 132332220127 its reverse (721022233231), we get a palindrome (853354453358).
The spelling of 132332220127 in words is "one hundred thirty-two billion, three hundred thirty-two million, two hundred twenty thousand, one hundred twenty-seven".
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