Base | Representation |
---|---|
bin | 11110000101101101101111… |
… | …110101000010000100111101 |
3 | 122100120000110220102001102111 |
4 | 132011231233311002010331 |
5 | 114321130231030431143 |
6 | 1145241241423254021 |
7 | 36605552461311322 |
oct | 3605555765020475 |
9 | 570500426361374 |
10 | 132334113530173 |
11 | 39190645165455 |
12 | 12a132a2a4a311 |
13 | 58ac090301a69 |
14 | 2497010662b49 |
15 | 10474a9a5c99d |
hex | 785b6fd4213d |
132334113530173 has 2 divisors, whose sum is σ = 132334113530174. Its totient is φ = 132334113530172.
The previous prime is 132334113530159. The next prime is 132334113530183. The reversal of 132334113530173 is 371035311433231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103699232291524 + 28634881238649 = 10183282^2 + 5351157^2 .
It is a cyclic number.
It is not a de Polignac number, because 132334113530173 - 25 = 132334113530141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132334113530183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66167056765086 + 66167056765087.
It is an arithmetic number, because the mean of its divisors is an integer number (66167056765087).
Almost surely, 2132334113530173 is an apocalyptic number.
It is an amenable number.
132334113530173 is a deficient number, since it is larger than the sum of its proper divisors (1).
132334113530173 is an equidigital number, since it uses as much as digits as its factorization.
132334113530173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 204120, while the sum is 40.
The spelling of 132334113530173 in words is "one hundred thirty-two trillion, three hundred thirty-four billion, one hundred thirteen million, five hundred thirty thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •